3x-2(16-2x)=10

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Solution for 3x-2(16-2x)=10 equation: 



3x-2(16-2x)=10

We move all terms to the left:

3x-2(16-2x)-(10)=0

We add all the numbers together, and all the variables

3x-2(-2x+16)-10=0

We multiply parentheses

3x+4x-32-10=0

We add all the numbers together, and all the variables

7x-42=0

We move all terms containing x to the left, all other terms to the right

7x=42

x=42/7

x=6

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