F=9/5c+33

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Solution for F=9/5c+33 equation: 



=9/5F+33

We move all terms to the left:

-(9/5F+33)=0



Domain of the equation: 5F+33)!=0

F∈R



We get rid of parentheses

-9/5F-33=0

We multiply all the terms by the denominator


-33*5F-9=0

Wy multiply elements

-165F-9=0

We move all terms containing F to the left, all other terms to the right

-165F=9

F=9/-165

F=-3/55

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