4(m+1)+3=19

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Solution for 4(m+1)+3=19 equation: 



4(m+1)+3=19

We move all terms to the left:

4(m+1)+3-(19)=0

We add all the numbers together, and all the variables

4(m+1)-16=0

We multiply parentheses

4m+4-16=0

We add all the numbers together, and all the variables

4m-12=0

We move all terms containing m to the left, all other terms to the right

4m=12

m=12/4

m=3

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