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=(9/5F)+32
We move all terms to the left:
-((9/5F)+32)=0
Domain of the equation: 5F)+32)!=0We add all the numbers together, and all the variables
F!=0/1
F!=0
F∈R
-((+9/5F)+32)=0
We multiply all the terms by the denominator
-((+9=0
We add all the numbers together, and all the variables
=0
F=0/1
F=0
Równanie nie ma rozwiązania
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