If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/3(9m+3)=3m+1
We move all terms to the left:
1/3(9m+3)-(3m+1)=0
Domain of the equation: 3(9m+3)!=0We get rid of parentheses
m∈R
1/3(9m+3)-3m-1=0
We multiply all the terms by the denominator
-3m*3(9m+3)-1*3(9m+3)+1=0
Wy multiply elements
-9m^2(9-3m(9+1=0
| 3/8n+10=6 | | F(x)=3×^+×+2 | | 9x-1/3x=3 | | 12-9c=15 | | (7x)(2x)=108 | | 11/12x=242 | | a/9+9=2/3 | | 2(y-6)-(3-7y)=-15 | | 11(p-3)=6(p+3) | | 2x÷2=-52 | | 8(5c+6)=5(8c-1) | | 4(a+1)=a+3 | | 0.8m6.4=0.8m | | 8v-13=15 | | 12a-4=3 | | 9(k-4)=4-3 | | -5x+4x=10-5-16 | | 4b^2-5b=-10 | | 2(2x-)=-34 | | (x+3)^2=30 | | 15x=3x² | | 7=14-6k | | ((2x-1)+(3x+4/2x+5))/((2x+5)-(3x+4/2x-1))=0 | | X+6=1-4x | | 7=14-5k | | 10a^2+7=-142 | | 10(n^2-1)+2n-5=(2n+5)(n-1) | | 2m^2+6=-5 | | (43)(212)=(43)(34)(h) | | 5n^2-4=-28 | | 3(x-6)-8x=-2+5(2x±1) | | 5z-3=6z-3 |