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(F)=5F^2-2(F)+3
We move all terms to the left:
(F)-(5F^2-2(F)+3)=0
We get rid of parentheses
-5F^2+F+2F-3=0
We add all the numbers together, and all the variables
-5F^2+3F-3=0
a = -5; b = 3; c = -3;
Δ = b2-4ac
Δ = 32-4·(-5)·(-3)
Δ = -51
Delta is less than zero, so there is no solution for the equation
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