F(x)=5/0x

Solution for F(x)=5/0x equation:

(F)=5/0F

We move all terms to the left:

(F)-(5/0F)=0


Domain of the equation: 0F)!=0

F!=0/1

F!=0

F∈R


We add all the numbers together, and all the variables

F-(+5/0F)=0

We get rid of parentheses

F-5/0F=0

We multiply all the terms by the denominator


F*0F-5=0

Wy multiply elements

0F^2-5=0

We add all the numbers together, and all the variables

F^2-5=0

a = 1; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·1·(-5)
Δ = 20
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20}=\sqrt{4*5}=\sqrt{4}*\sqrt{5}=2\sqrt{5}$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{5}}{2*1}=\frac{0-2\sqrt{5}}{2}
=-\frac{2\sqrt{5}}{2}
=-\sqrt{5}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{5}}{2*1}=\frac{0+2\sqrt{5}}{2}
=\frac{2\sqrt{5}}{2}
=\sqrt{5}
$