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(F)=5(F+1/5)
We move all terms to the left:
(F)-(5(F+1/5))=0
We add all the numbers together, and all the variables
F-(5(+F+1/5))=0
We multiply all the terms by the denominator
F*5))-(5(+F+1=0
We add all the numbers together, and all the variables
F+F*5))-(5(+1=0
Wy multiply elements
5F^2+F+1=0
a = 5; b = 1; c = +1;
Δ = b2-4ac
Δ = 12-4·5·1
Δ = -19
Delta is less than zero, so there is no solution for the equation
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