F(a)=a2+4+a

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Solution for F(a)=a2+4+a equation: 



(F)=F2+4+F

We move all terms to the left:

(F)-(F2+4+F)=0

We add all the numbers together, and all the variables

-(+F^2+F+4)+F=0

We get rid of parentheses

-F^2-F+F-4=0

We add all the numbers together, and all the variables

-1F^2-4=0

a = -1; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·(-1)·(-4)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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