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(F)=3F^2+5
We move all terms to the left:
(F)-(3F^2+5)=0
We get rid of parentheses
-3F^2+F-5=0
a = -3; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·(-3)·(-5)
Δ = -59
Delta is less than zero, so there is no solution for the equation
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