2(u-3)(-u+1)=0

Solution for 2(u-3)(-u+1)=0 equation:

2(u-3)(-u+1)=0

We add all the numbers together, and all the variables

2(u-3)(-1u+1)=0

We multiply parentheses ..

2(-1u^2+u+3u-3)=0

We multiply parentheses

-2u^2+2u+6u-6=0

We add all the numbers together, and all the variables

-2u^2+8u-6=0

a = -2; b = 8; c = -6;
Δ = b2-4ac
Δ = 82-4·(-2)·(-6)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4}{2*-2}=\frac{-12}{-4}
=+3
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4}{2*-2}=\frac{-4}{-4}
=1
$