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(F)=3F/2F-6
We move all terms to the left:
(F)-(3F/2F-6)=0
Domain of the equation: 2F-6)!=0We get rid of parentheses
F∈R
F-3F/2F+6=0
We multiply all the terms by the denominator
F*2F-3F+6*2F=0
We add all the numbers together, and all the variables
-3F+F*2F+6*2F=0
Wy multiply elements
2F^2-3F+12F=0
We add all the numbers together, and all the variables
2F^2+9F=0
a = 2; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·2·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*2}=\frac{-18}{4} =-4+1/2 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*2}=\frac{0}{4} =0 $
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