3(2x+59)=(12x-19)12

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Solution for 3(2x+59)=(12x-19)12 equation: 



3(2x+59)=(12x-19)12

We move all terms to the left:

3(2x+59)-((12x-19)12)=0

We multiply parentheses

6x-((12x-19)12)+177=0



We calculate terms in parentheses: -((12x-19)12), so:

(12x-19)12

We multiply parentheses

144x-228

Back to the equation:

-(144x-228)



We get rid of parentheses

6x-144x+228+177=0

We add all the numbers together, and all the variables

-138x+405=0

We move all terms containing x to the left, all other terms to the right

-138x=-405

x=-405/-138

x=2+43/46

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