F(x)=2/9x+8

Solution for F(x)=2/9x+8 equation:

(F)=2/9F+8

We move all terms to the left:

(F)-(2/9F+8)=0


Domain of the equation: 9F+8)!=0

F∈R


We get rid of parentheses

F-2/9F-8=0

We multiply all the terms by the denominator


F*9F-8*9F-2=0

Wy multiply elements

9F^2-72F-2=0

a = 9; b = -72; c = -2;
Δ = b2-4ac
Δ = -722-4·9·(-2)
Δ = 5256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5256}=\sqrt{36*146}=\sqrt{36}*\sqrt{146}=6\sqrt{146}$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-6\sqrt{146}}{2*9}=\frac{72-6\sqrt{146}}{18}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+6\sqrt{146}}{2*9}=\frac{72+6\sqrt{146}}{18}
$