A+2=7/(a+2)-5

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Solution for A+2=7/(a+2)-5 equation: 



+2=7/(A+2)-5

We move all terms to the left:

+2-(7/(A+2)-5)=0



Domain of the equation: (A+2)-5)!=0

A∈R



We multiply all the terms by the denominator


-(7+2*(A+2)-5)=0



We calculate terms in parentheses: -(7+2*(A+2)-5), so:

7+2*(A+2)-5

determiningTheFunctionDomain
2*(A+2)+7-5

We add all the numbers together, and all the variables

2*(A+2)+2

We multiply parentheses

2A+4+2

We add all the numbers together, and all the variables

2A+6

Back to the equation:

-(2A+6)



We get rid of parentheses

-2A-6=0

We move all terms containing A to the left, all other terms to the right

-2A=6

A=6/-2

A=-3

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