F(x)=2(3x-5)+8(4x+7)

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Solution for F(x)=2(3x-5)+8(4x+7) equation: 



(F)=2(3F-5)+8(4F+7)

We move all terms to the left:

(F)-(2(3F-5)+8(4F+7))=0



We calculate terms in parentheses: -(2(3F-5)+8(4F+7)), so:

2(3F-5)+8(4F+7)

We multiply parentheses

6F+32F-10+56

We add all the numbers together, and all the variables

38F+46

Back to the equation:

-(38F+46)



We get rid of parentheses

F-38F-46=0

We add all the numbers together, and all the variables

-37F-46=0

We move all terms containing F to the left, all other terms to the right

-37F=46

F=46/-37

F=-1+9/37

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