2/3(6c-18)=3/4(8c+32)=-18

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Solution for 2/3(6c-18)=3/4(8c+32)=-18 equation: 



2/3(6c-18)=3/4(8c+32)=-18

We move all terms to the left:

2/3(6c-18)-(3/4(8c+32))=0



Domain of the equation: 3(6c-18)!=0

c∈R





Domain of the equation: 4(8c+32))!=0

c∈R



We calculate fractions


(8c8/(3(6c-18)*4(8c+32)))+(-9c6/(3(6c-18)*4(8c+32)))=0



We calculate terms in parentheses: +(8c8/(3(6c-18)*4(8c+32))), so:

8c8/(3(6c-18)*4(8c+32))

We multiply all the terms by the denominator


8c8

We add all the numbers together, and all the variables

8c^8

We do not support ecpression: c^8

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