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(F)=1/F+5
We move all terms to the left:
(F)-(1/F+5)=0
Domain of the equation: F+5)!=0We get rid of parentheses
F∈R
F-1/F-5=0
We multiply all the terms by the denominator
F*F-5*F-1=0
We add all the numbers together, and all the variables
-5F+F*F-1=0
Wy multiply elements
F^2-5F-1=0
a = 1; b = -5; c = -1;
Δ = b2-4ac
Δ = -52-4·1·(-1)
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{29}}{2*1}=\frac{5-\sqrt{29}}{2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{29}}{2*1}=\frac{5+\sqrt{29}}{2} $
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