(2x-6)-4(3x-2)=6-2(8x-1)

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Solution for (2x-6)-4(3x-2)=6-2(8x-1) equation:



(2x-6)-4(3x-2)=6-2(8x-1)
We move all terms to the left:
(2x-6)-4(3x-2)-(6-2(8x-1))=0
We multiply parentheses
(2x-6)-12x-(6-2(8x-1))+8=0
We get rid of parentheses
2x-12x-(6-2(8x-1))-6+8=0
We calculate terms in parentheses: -(6-2(8x-1)), so:
6-2(8x-1)
determiningTheFunctionDomain -2(8x-1)+6
We multiply parentheses
-16x+2+6
We add all the numbers together, and all the variables
-16x+8
Back to the equation:
-(-16x+8)
We add all the numbers together, and all the variables
-10x-(-16x+8)+2=0
We get rid of parentheses
-10x+16x-8+2=0
We add all the numbers together, and all the variables
6x-6=0
We move all terms containing x to the left, all other terms to the right
6x=6
x=6/6
x=1

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