F(x)=1/8x+4

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Solution for F(x)=1/8x+4 equation:



(F)=1/8F+4
We move all terms to the left:
(F)-(1/8F+4)=0
Domain of the equation: 8F+4)!=0
F∈R
We get rid of parentheses
F-1/8F-4=0
We multiply all the terms by the denominator
F*8F-4*8F-1=0
Wy multiply elements
8F^2-32F-1=0
a = 8; b = -32; c = -1;
Δ = b2-4ac
Δ = -322-4·8·(-1)
Δ = 1056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1056}=\sqrt{16*66}=\sqrt{16}*\sqrt{66}=4\sqrt{66}$
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-4\sqrt{66}}{2*8}=\frac{32-4\sqrt{66}}{16} $
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+4\sqrt{66}}{2*8}=\frac{32+4\sqrt{66}}{16} $

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