5(x-7)=10(x-2)

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Solution for 5(x-7)=10(x-2) equation: 



5(x-7)=10(x-2)

We move all terms to the left:

5(x-7)-(10(x-2))=0

We multiply parentheses

5x-(10(x-2))-35=0



We calculate terms in parentheses: -(10(x-2)), so:

10(x-2)

We multiply parentheses

10x-20

Back to the equation:

-(10x-20)



We get rid of parentheses

5x-10x+20-35=0

We add all the numbers together, and all the variables

-5x-15=0

We move all terms containing x to the left, all other terms to the right

-5x=15

x=15/-5

x=-3

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