F(x)=-x2-10x-16

Solution for F(x)=-x2-10x-16 equation:

(F)=-F2-10F-16

We move all terms to the left:

(F)-(-F2-10F-16)=0

We add all the numbers together, and all the variables

-(-1F^2-10F-16)+F=0

We get rid of parentheses

1F^2+10F+F+16=0

We add all the numbers together, and all the variables

F^2+11F+16=0

a = 1; b = 11; c = +16;
Δ = b2-4ac
Δ = 112-4·1·16
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{57}}{2*1}=\frac{-11-\sqrt{57}}{2}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{57}}{2*1}=\frac{-11+\sqrt{57}}{2}
$