F(-12)=4/3x+12

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Solution for F(-12)=4/3x+12 equation: 



(-12)=4/3F+12

We move all terms to the left:

(-12)-(4/3F+12)=0



Domain of the equation: 3F+12)!=0

F∈R



We add all the numbers together, and all the variables

-(4/3F+12)-12=0

We get rid of parentheses

-4/3F-12-12=0

We multiply all the terms by the denominator


-12*3F-12*3F-4=0

Wy multiply elements

-36F-36F-4=0

We add all the numbers together, and all the variables

-72F-4=0

We move all terms containing F to the left, all other terms to the right

-72F=4

F=4/-72

F=-1/18

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