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(F)=-(F-20)(F-100)
We move all terms to the left:
(F)-(-(F-20)(F-100))=0
We multiply parentheses ..
-(-(+F^2-100F-20F+2000))+F=0
We calculate terms in parentheses: -(-(+F^2-100F-20F+2000)), so:We get rid of parentheses
-(+F^2-100F-20F+2000)
We get rid of parentheses
-F^2+100F+20F-2000
We add all the numbers together, and all the variables
-1F^2+120F-2000
Back to the equation:
-(-1F^2+120F-2000)
1F^2-120F+F+2000=0
We add all the numbers together, and all the variables
F^2-119F+2000=0
a = 1; b = -119; c = +2000;
Δ = b2-4ac
Δ = -1192-4·1·2000
Δ = 6161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-119)-\sqrt{6161}}{2*1}=\frac{119-\sqrt{6161}}{2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-119)+\sqrt{6161}}{2*1}=\frac{119+\sqrt{6161}}{2} $
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