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t/2-5/2=5
We move all terms to the left:
t/2-5/2-(5)=0
determiningTheFunctionDomain t/2-5-5/2=0
We multiply all the terms by the denominator
t-5-5*2=0
We add all the numbers together, and all the variables
t-15=0
We move all terms containing t to the left, all other terms to the right
t=15
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