F(n)=80+12(n-1)

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Solution for F(n)=80+12(n-1) equation: 



(F)=80+12(F-1)

We move all terms to the left:

(F)-(80+12(F-1))=0



We calculate terms in parentheses: -(80+12(F-1)), so:

80+12(F-1)

determiningTheFunctionDomain
12(F-1)+80

We multiply parentheses

12F-12+80

We add all the numbers together, and all the variables

12F+68

Back to the equation:

-(12F+68)



We get rid of parentheses

F-12F-68=0

We add all the numbers together, and all the variables

-11F-68=0

We move all terms containing F to the left, all other terms to the right

-11F=68

F=68/-11

F=-6+2/11

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