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7t+3=2t(5/2)
We move all terms to the left:
7t+3-(2t(5/2))=0
We add all the numbers together, and all the variables
7t-(2t(+5/2))+3=0
We multiply all the terms by the denominator
7t*2))-(2t(+5+3*2))=0
We add all the numbers together, and all the variables
7t*2))-(2t11)=0
We add all the numbers together, and all the variables
7t*2))-2t11=0
Wy multiply elements
14t^2=0
a = 14; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·14·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$t=\frac{-b}{2a}=\frac{0}{28}=0$
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