F(n)=2n(3n-6)/3

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Solution for F(n)=2n(3n-6)/3 equation: 



(F)=2F(3F-6)/3

We move all terms to the left:

(F)-(2F(3F-6)/3)=0

We multiply all the terms by the denominator


F*3)-(2F(3F-6)=0

Wy multiply elements

3F^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$F=\frac{-b}{2a}=\frac{0}{6}=0$

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