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-2x(x-9)-29=-11
We move all terms to the left:
-2x(x-9)-29-(-11)=0
We add all the numbers together, and all the variables
-2x(x-9)-18=0
We multiply parentheses
-2x^2+18x-18=0
a = -2; b = 18; c = -18;
Δ = b2-4ac
Δ = 182-4·(-2)·(-18)
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6\sqrt{5}}{2*-2}=\frac{-18-6\sqrt{5}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6\sqrt{5}}{2*-2}=\frac{-18+6\sqrt{5}}{-4} $
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