F(9)=2/3x-5

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Solution for F(9)=2/3x-5 equation: 



(9)=2/3F-5

We move all terms to the left:

(9)-(2/3F-5)=0



Domain of the equation: 3F-5)!=0

F∈R



We get rid of parentheses

-2/3F+5+9=0

We multiply all the terms by the denominator


5*3F+9*3F-2=0

Wy multiply elements

15F+27F-2=0

We add all the numbers together, and all the variables

42F-2=0

We move all terms containing F to the left, all other terms to the right

42F=2

F=2/42

F=1/21

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