-12(-2a+12)=3(4+10a)+7a

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Solution for -12(-2a+12)=3(4+10a)+7a equation:



-12(-2a+12)=3(4+10a)+7a
We move all terms to the left:
-12(-2a+12)-(3(4+10a)+7a)=0
We add all the numbers together, and all the variables
-12(-2a+12)-(3(10a+4)+7a)=0
We multiply parentheses
24a-(3(10a+4)+7a)-144=0
We calculate terms in parentheses: -(3(10a+4)+7a), so:
3(10a+4)+7a
We add all the numbers together, and all the variables
7a+3(10a+4)
We multiply parentheses
7a+30a+12
We add all the numbers together, and all the variables
37a+12
Back to the equation:
-(37a+12)
We get rid of parentheses
24a-37a-12-144=0
We add all the numbers together, and all the variables
-13a-156=0
We move all terms containing a to the left, all other terms to the right
-13a=156
a=156/-13
a=-12

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