7(1-t)=-3(t-2)

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Solution for 7(1-t)=-3(t-2) equation: 



7(1-t)=-3(t-2)

We move all terms to the left:

7(1-t)-(-3(t-2))=0

We add all the numbers together, and all the variables

7(-1t+1)-(-3(t-2))=0

We multiply parentheses

-7t-(-3(t-2))+7=0



We calculate terms in parentheses: -(-3(t-2)), so:

-3(t-2)

We multiply parentheses

-3t+6

Back to the equation:

-(-3t+6)



We get rid of parentheses

-7t+3t-6+7=0

We add all the numbers together, and all the variables

-4t+1=0

We move all terms containing t to the left, all other terms to the right

-4t=-1

t=-1/-4

t=1/4

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