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(4)=(1/3)F
We move all terms to the left:
(4)-((1/3)F)=0
Domain of the equation: 3)F)!=0We add all the numbers together, and all the variables
F!=0/1
F!=0
F∈R
-((+1/3)F)+4=0
We multiply all the terms by the denominator
-((+1+4*3)F)=0
We calculate terms in parentheses: -((+1+4*3)F), so:F=0/-13
(+1+4*3)F
We add all the numbers together, and all the variables
13F
Back to the equation:
-(13F)
F=0
Równanie nie ma rozwiązania
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