F(3)=x3-5x-4x+20

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Solution for F(3)=x3-5x-4x+20 equation: 



(3)=F3-5F-4F+20

We move all terms to the left:

(3)-(F3-5F-4F+20)=0

We add all the numbers together, and all the variables

-(+F^3-9F+20)+3=0

We get rid of parentheses

-F^3+9F-20+3=0

We do not support eFpression: F^3

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