3(2x)+4x=-(3-2x)+7+x

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Solution for 3(2x)+4x=-(3-2x)+7+x equation: 



3(2x)+4x=-(3-2x)+7+x

We move all terms to the left:

3(2x)+4x-(-(3-2x)+7+x)=0

We add all the numbers together, and all the variables

32x+4x-(-(-2x+3)+7+x)=0

We add all the numbers together, and all the variables

36x-(-(-2x+3)+7+x)=0



We calculate terms in parentheses: -(-(-2x+3)+7+x), so:

-(-2x+3)+7+x

determiningTheFunctionDomain
-(-2x+3)+x+7

We add all the numbers together, and all the variables

x-(-2x+3)+7

We get rid of parentheses

x+2x-3+7

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We get rid of parentheses

36x-3x-4=0

We add all the numbers together, and all the variables

33x-4=0

We move all terms containing x to the left, all other terms to the right

33x=4

x=4/33

x=4/33

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