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(0)=F(18-F)
We move all terms to the left:
(0)-(F(18-F))=0
We add all the numbers together, and all the variables
-(F(-1F+18))+0=0
We add all the numbers together, and all the variables
-(F(-1F+18))=0
We calculate terms in parentheses: -(F(-1F+18)), so:We get rid of parentheses
F(-1F+18)
We multiply parentheses
-1F^2+18F
Back to the equation:
-(-1F^2+18F)
1F^2-18F=0
We add all the numbers together, and all the variables
F^2-18F=0
a = 1; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·1·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*1}=\frac{0}{2} =0 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*1}=\frac{36}{2} =18 $
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