n*(3-2)=12

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Solution for n*(3-2)=12 equation: 



n(3-2)=12

We move all terms to the left:

n(3-2)-(12)=0

We add all the numbers together, and all the variables

n1-12=0

We add all the numbers together, and all the variables

n-12=0

We move all terms containing n to the left, all other terms to the right

n=12

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