F(-5)=(x+40)+(3x-20)

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Solution for F(-5)=(x+40)+(3x-20) equation: 



(-5)=(F+40)+(3F-20)

We move all terms to the left:

(-5)-((F+40)+(3F-20))=0

We add all the numbers together, and all the variables

-((F+40)+(3F-20))-5=0



We calculate terms in parentheses: -((F+40)+(3F-20)), so:

(F+40)+(3F-20)

We get rid of parentheses

F+3F+40-20

We add all the numbers together, and all the variables

4F+20

Back to the equation:

-(4F+20)



We get rid of parentheses

-4F-20-5=0

We add all the numbers together, and all the variables

-4F-25=0

We move all terms containing F to the left, all other terms to the right

-4F=25

F=25/-4

F=-6+1/4

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