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3x-9(x-2)=6(3+x)
We move all terms to the left:
3x-9(x-2)-(6(3+x))=0
We add all the numbers together, and all the variables
3x-9(x-2)-(6(x+3))=0
We multiply parentheses
3x-9x-(6(x+3))+18=0
We calculate terms in parentheses: -(6(x+3)), so:We add all the numbers together, and all the variables
6(x+3)
We multiply parentheses
6x+18
Back to the equation:
-(6x+18)
-6x-(6x+18)+18=0
We get rid of parentheses
-6x-6x-18+18=0
We add all the numbers together, and all the variables
-12x=0
x=0/-12
x=0
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