D/12x2+6=7

Solution for D/12x2+6=7 equation:

/12D^2+6=7

We move all terms to the left:

/12D^2+6-(7)=0


Domain of the equation: 12D^2!=0

D^2!=0/12

D^2!=√0

D!=0

D∈R


We add all the numbers together, and all the variables

/12D^2-1=0

We multiply all the terms by the denominator


-1*12D^2+=0

We add all the numbers together, and all the variables

-1*12D^2=0

Wy multiply elements

-12D^2=0

a = -12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-12)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$D=\frac{-b}{2a}=\frac{0}{-24}=0$