C=d-1-(3d+4)-(7d+5)-5

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Solution for C=d-1-(3d+4)-(7d+5)-5 equation: 



=C-1-(3C+4)-(7C+5)-5

We move all terms to the left:

-(C-1-(3C+4)-(7C+5)-5)=0



We calculate terms in parentheses: -(C-1-(3C+4)-(7C+5)-5), so:

C-1-(3C+4)-(7C+5)-5

determiningTheFunctionDomain
C-(3C+4)-(7C+5)-1-5

We add all the numbers together, and all the variables

C-(3C+4)-(7C+5)-6

We get rid of parentheses

C-3C-7C-4-5-6

We add all the numbers together, and all the variables

-9C-15

Back to the equation:

-(-9C-15)



We get rid of parentheses

9C+15=0

We move all terms containing C to the left, all other terms to the right

9C=-15

C=-15/9

C=-1+2/3

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