(2x-2)(x+1)+5=0

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Solution for (2x-2)(x+1)+5=0 equation: 



(2x-2)(x+1)+5=0

We multiply parentheses ..

(+2x^2+2x-2x-2)+5=0

We get rid of parentheses

2x^2+2x-2x-2+5=0

We add all the numbers together, and all the variables

2x^2+3=0

a = 2; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·2·3
Δ = -24
Delta is less than zero, so there is no solution for the equation

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