(2/3)x+(1/2)x=(1/6)x+3

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Solution for (2/3)x+(1/2)x=(1/6)x+3 equation: 



(2/3)x+(1/2)x=(1/6)x+3

We move all terms to the left:

(2/3)x+(1/2)x-((1/6)x+3)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 6)x+3)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)x+(+1/2)x-((+1/6)x+3)=0

We multiply parentheses

2x^2+x^2-((+1/6)x+3)=0

We multiply all the terms by the denominator


2x^2*6)x+3)+x^2*6)x+3)-((+1=0

Wy multiply elements

72x^4=0

We do not support expression: x^4

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