C+22=2c+48=6c+7

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Solution for C+22=2c+48=6c+7 equation:



+22=2C+48=6C+7
We move all terms to the left:
+22-(2C+48)=0
We get rid of parentheses
-2C-48+22=0
We add all the numbers together, and all the variables
-2C-26=0
We move all terms containing C to the left, all other terms to the right
-2C=26
C=26/-2
C=-13

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