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2x-5=2x(x-5)
We move all terms to the left:
2x-5-(2x(x-5))=0
We calculate terms in parentheses: -(2x(x-5)), so:We get rid of parentheses
2x(x-5)
We multiply parentheses
2x^2-10x
Back to the equation:
-(2x^2-10x)
-2x^2+2x+10x-5=0
We add all the numbers together, and all the variables
-2x^2+12x-5=0
a = -2; b = 12; c = -5;
Δ = b2-4ac
Δ = 122-4·(-2)·(-5)
Δ = 104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{104}=\sqrt{4*26}=\sqrt{4}*\sqrt{26}=2\sqrt{26}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{26}}{2*-2}=\frac{-12-2\sqrt{26}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{26}}{2*-2}=\frac{-12+2\sqrt{26}}{-4} $
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