B=5/2(j-50)

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Solution for B=5/2(j-50) equation:



=5/2(B-50)
We move all terms to the left:
-(5/2(B-50))=0
Domain of the equation: 2(B-50))!=0
B∈R
We multiply all the terms by the denominator
-(5=0
We add all the numbers together, and all the variables
=0
B=0/1
B=0

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