3y+4=y+19

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Solution for 3y+4=y+19 equation: 



3y+4=y+19

We move all terms to the left:

3y+4-(y+19)=0

We get rid of parentheses

3y-y-19+4=0

We add all the numbers together, and all the variables

2y-15=0

We move all terms containing y to the left, all other terms to the right

2y=15

y=15/2

y=7+1/2

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