B=3(n+1)-2=

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Solution for B=3(n+1)-2= equation: 



=3(B+1)-2=

We move all terms to the left:

-(3(B+1)-2)=0



We calculate terms in parentheses: -(3(B+1)-2), so:

3(B+1)-2

We multiply parentheses

3B+3-2

We add all the numbers together, and all the variables

3B+1

Back to the equation:

-(3B+1)



We get rid of parentheses

-3B-1=0

We move all terms containing B to the left, all other terms to the right

-3B=1

B=1/-3

B=-1/3

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