B=2n+2+2(n-1)=

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Solution for B=2n+2+2(n-1)= equation: 



=2B+2+2(B-1)=

We move all terms to the left:

-(2B+2+2(B-1))=0



We calculate terms in parentheses: -(2B+2+2(B-1)), so:

2B+2+2(B-1)

determiningTheFunctionDomain
2B+2(B-1)+2

We multiply parentheses

2B+2B-2+2

We add all the numbers together, and all the variables

4B

Back to the equation:

-(4B)



B=0/-4

B=0

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