B=((5x+2)(6x+12)/((x+1)(x-3)))

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Solution for B=((5x+2)(6x+12)/((x+1)(x-3))) equation:



=((5B+2)(6B+12)/((B+1)(B-3)))
We move all terms to the left:
-(((5B+2)(6B+12)/((B+1)(B-3))))=0
Domain of the equation: ((B+1)(B-3))))!=0
B∈R
We multiply parentheses ..
-(((+30B^2+60B+12B+24)/((B+1)(B-3))))=0
We multiply all the terms by the denominator
-(((+30B^2+60B+12B+24)=0
We calculate terms in parentheses: -(((+30B^2+60B+12B+24), so:
((+30B^2+60B+12B+24
We calculate terms in parentheses: -(((+30B^2+60B+12B+24), so:
((+30B^2+60B+12B+24
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((+30B^2+60B+12B+24
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((+30B^2+60B+12B+24
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((+30B^2+60B+12B+24
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((+30B^2+60B+12B+24
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((+30B^2+60B+12B+24
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((+30B^2+60B+12B+24
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((+30B^2+60B+12B+24
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((+30B^2+60B+12B+24
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((+30B^2+60B+12B+24
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